A 45ml of a 4M solution of CaBr2 contains how many grams of CaBr2?

Understanding Molarity Calculation

Molarity is a concentration unit that represents the number of moles of solute present per liter of solution. In this case, we are given a 45ml of a 4M solution of CaBr2 and we need to determine how many grams of CaBr2 are present in this solution.

Molarity Calculation

The formula to calculate molarity is: M = n/V, where M is the molarity, n is the number of moles of solute, and V is the volume of the solution in liters.

Given data:

Molarity (M) = 4M

Volume (V) = 45mL = 0.045L

Calculate the number of moles of CaBr2:

n = (4)(0.045) = 0.18 moles

Mass Calculation

The relationship between mass and moles of any substance is given by the formula: n = W/M, where W is the given mass and M is the molar mass.

Given data:

Required mass of calcium bromide (W) = 35.98 grams

Molar mass of CaBr2 = 199.89g/mol

Calculate the mass of CaBr2:

Mass of CaBr2 = (0.18 mol)(199.89 g/mol) = 35.98 grams

Therefore, the required mass of CaBr2 in a 45ml of a 4M solution is 35.98 grams.

What is molarity?

Molarity is a concentration unit that represents the number of moles of solute present per liter of solution. It is calculated using the formula M = n/V, where M is the molarity, n is the number of moles of solute, and V is the volume of the solution in liters.