# A Fun Chemistry Problem to Solve!

## How Much Calcium Carbonate Was Used?

A pure sample of calcium carbonate produced 0.998 g of CO2. What was the mass of the calcium carbonate used?

## Answer:

The mass of the calcium carbonate used was 2.272 grams.

If you're curious about how we arrived at this answer, let's break it down step by step:

## Step 1: Calculate the Molar Mass

The molar mass of calcium carbonate (CaCO3) is 100.1 g/mol and the molar mass of carbon dioxide (CO2) is 44.01 g/mol.

## Step 2: Convert Mass of CO2 to Moles

0.998 g CO2 is equivalent to 0.0227 mol CO2.

## Step 3: Use Stoichiometry

For every 1 mole of CaCO3, 1 mole of CO2 is produced according to the balanced chemical equation.

## Step 4: Convert Moles of CaCO3 to Grams

0.0227 mol CaCO3 corresponds to 2.272 g of CaCO3.

And that's how we found out that the mass of the calcium carbonate used was 2.272 grams. Chemistry can be fun and rewarding when you solve these kinds of problems!