Ampasanya adalah 6.00 M

Molarity Calculation of HCl Solution

A 1.00 L volume of HCl reacted completely with 2.00 L of 1.50 M Ca(OH)2 according to the balanced chemical equation below.

2HCl + Ca(OH)2 → CaCl2 + 2H2O

What was the molarity of the HCl solution?

A. 0.375 M

B. 1.50 M

C. 3.00 M

D. 6.00 M

The answer is D

The molarity of the HCl solution is 6.00 M

Calculation:

2HCl + Ca(OH)2 → CaCl2 + 2H2O

Step 1: Find the moles of Ca(OH)2

= molarity x volume

= 2 L x 1.5 mol/L = 3.00 moles

Step 2: Use the mole ratio of HCl : Ca(OH)2 to calculate the moles of HCl

That is Ca(OH)2 : HCl is 2:1 therefore the moles of HCl = 3.00 moles x 2 = 6.00 moles

Step 3: Find the molarity of HCl

Molarity of HCl = moles of HCl / volume in liters of HCl

= 6.00 moles / 1 L = 6.00 M