Calculating Temperature Using Combined Gas Law

Calculating Temperature of a Gas

If a gas occupies a volume of 3.50 L at a temperature of 10.0°C, what will be the temperature of the gas at a volume of 3.99 L?

Explanation:

We can use the combined gas law to solve this problem, which relates the pressure, volume, and temperature of a gas:

(P₁V₁) / T₁ = (P₂V₂) / T₂

where P is the pressure, V is the volume, and T is the temperature.

We can assume that the pressure and amount of gas are constant, so we can simplify the equation to:

V₁ / T₁ = V₂ / T₂

Substituting the given values, we get:

3.50 L / 283.15 K = 3.99 L / T₂

Solving for T₂, we get:

T₂ = (3.99 L / 3.50 L) x 283.15 K

T₂ = 322.4 K

Therefore, the temperature of the gas at a volume of 3.99 L is approximately 322.4 K.