# Calculation of Molar Concentration and Ion Concentration in Sodium Sulfite Solution

## What are the calculations involved in determining the molar concentration of sodium sulfite and the concentration of sodium ions in the solution?

a. How do we calculate the molar concentration of sodium sulfite in the solution?

b. What is the method to find the concentration of sodium ions in the solution?

## Calculation of Molar Concentration and Ion Concentration

a. The molar concentration of sodium sulfite in the solution can be calculated by dividing the moles of sodium sulfite by the volume of the solution.

b. The concentration of sodium ions in the solution can be determined by considering the dissociation of sodium sulfite and multiplying the molar concentration of sodium sulfite by the number of sodium ions produced per formula unit.

To calculate the molar concentration of sodium sulfite, we need to determine the number of moles of sodium sulfite in the solution. The number of moles can be calculated by dividing the mass of sodium sulfite by its molar mass. Sodium sulfite (Na2SO3) has a molar mass of 126.04 g/mol, so the number of moles is 15.6 g / 126.04 g/mol = 0.124 mol. The molar concentration is then given by dividing the number of moles by the volume of the solution in liters: 0.124 mol / 0.456 L = 0.272 M.

Sodium sulfite dissociates into two sodium ions (Na+) per formula unit. Therefore, the concentration of sodium ions is equal to twice the molar concentration of sodium sulfite: 2 * 0.272 M = 0.544 M.

By understanding these calculations, we can determine the molar concentration of sodium sulfite and the concentration of sodium ions in the solution accurately. It showcases the importance of chemistry in analyzing solutions and their components.