Chemical Reaction: Ammonia and Sulfuric Acid Producing Ammonium Sulfate

The chemical equation

The chemical equation shows how ammonia reacts with sulfuric acid to produce ammonium sulfate:

2NH₃(aq) + H₂SO₄(aq) → (NH₄)₂SO₄(aq)

Calculating the amount of Ammonium Sulfate

Question: How many grams of ammonium sulfate can be produced if 60.0 mol of sulfuric acid react with an excess of ammonia?

Answer:

The balanced chemical reaction is: 2NH₃(aq) + H₂SO_{4)(aq) = (NH4)2SO4)(aq)}

We are given the amount of sulfuric acid to be used for the reaction. This will be the starting point of our calculations.

60.0 mol H2SO₄ * (1 mol (NH₄)₂SO₄ / 1 mol H₂SO₄) * (132.14 g (NH₄)₂SO₄ / 1 mol (NH₄)₂SO₄) = 7928.4 g (NH₄)₂SO₄

How many grams of ammonium sulfate are produced when 30.0 mol of ammonia react with excess sulfuric acid?

If 30.0 mol of ammonia are used in the reaction with excess sulfuric acid, the amount of ammonium sulfate produced can be calculated using a similar method as before. The molar mass of (NH₄)₂SO₄ is 132.14 g/mol.