# Chemical Reaction Rate Calculation

## What is the rate of appearance of Br2 at a certain moment in the chemical reaction?

Given the rate of disappearance of Br- at that same moment was determined to be 3.5 x 10-4 M/s.

## Rate of Appearance of Br2:

3.5 x 10-4 M/s

Chemical reactions involve the transformation of reactants into products. In the given reaction, the rate of disappearance of Br- is calculated to be 3.5 x 10-4 M/s at a specific moment. To determine the rate of appearance of Br2 at that same moment, we need to consider the stoichiometry of the reaction.

The chemical reaction provided involves the reaction of 5 moles of Br- with 1 mole of BrO3- and 6 moles of H+ to produce 3 moles of Br2 and 3 moles of H2O. By applying the rate proportions between Br- and Br2, we can determine the rate of appearance of Br2 by considering the stoichiometric coefficients.

Using the equation:

**(Rate of Br-) / -5 = (Rate of Br2) / 3**

We can then calculate the rate of appearance of Br2:

**Rate of Br2 = (3 * Rate of Br-) / -5**

Substitute the given rate of disappearance of Br- (3.5 x 10-4 M/s) into the equation:

**Rate of Br2 = (3 * -3.5 x 10-4 M/s) / -5**

**Rate of Br2 = 2.1 x 10-4 M/s**

Therefore, the rate of appearance of Br2 at that same moment in the chemical reaction is 2.1 x 10-4 M/s.