Chemical Reaction: Volume Calculation
What volume of O₂ at STP is required to oxidize 8.0 L of NO at STP to NO₂?
Final answer: To oxidize 8.0 L of NO at STP, 4.0 L of O₂ is needed.
What volume of NO₂ is produced at STP?
Final answer: The reaction produces 8.0 L of NO₂ at STP.
Answer:
The balanced chemical equation for the reaction of nitric oxide (NO) with oxygen (O2) to form nitrogen dioxide (NO2) is 2NO + O2 → 2NO2. This shows that the reaction consumes nitric oxide and oxygen in a 2:1 ratio and produces nitrogen dioxide in the same volume as the nitric oxide consumed, at Standard Temperature and Pressure (STP).
To oxidize 8.0 L of NO to NO2, as per the chemical equation, we need half the volume of O2, which is 4.0 L. Furthermore, the volume of NO2 produced as a result of this reaction would be the same as the starting volume of NO, so 8.0 L of NO2 will be produced. These volumes are all calculated at STP.
Chemical reactions involve the conversion of reactants into products through the breaking and formation of chemical bonds. In this specific reaction, the NO and O2 molecules react to produce NO2 molecules while conserving mass and volume, as dictated by the balanced equation.
Therefore, to accurately determine the required volumes of gases for a reaction at STP, one must consider the stoichiometry of the reaction and the ideal gas law.