Chemistry Challenge: Calculate the Volume of CaCl2 Solution

How many mL of 1.81 M CaCl2 have 18.4 g of CaCl2 in them?

To calculate the volume of CaCl2 solution needed to contain 18.4 g of CaCl2, we need to use the molarity formula:

Molarity Formula:

Molarity (M) = moles of solute (n) / liters of solution (V)

First, we need to determine the number of moles of CaCl2 in 18.4 g. This can be done by using the molar mass of CaCl2, which is 110.98 g/mol.

Number of moles = given mass / molar mass

Number of moles = 18.4 g / 110.98 g/mol = 0.1656 mol

Next, we can use the molarity formula to calculate the volume of the solution:

1.81 M = 0.1656 mol / V

V = 0.1656 mol / 1.81 M = 0.0915 L = 91.5 mL

Therefore, 91.5 mL of 1.81 M CaCl2 solution is needed to contain 18.4 g of CaCl2.