Chemistry Problem Solving: Determining Molecular Weight of a Gas

What is the molecular weight of a gas if 7.46 mg of the gas occupies 2899 mL at 849 mm Hg and 27.63°C? The molecular weight of the gas can be determined using the Ideal Gas Law by converting the given values to appropriate units, calculating the number of moles, and then dividing the mass of the gas by the number of moles.

Understanding the Ideal Gas Law

The Ideal Gas Law (PV = nRT) is a fundamental equation in chemistry that relates the pressure (P), volume (V), number of moles of gas (n), ideal gas constant (R), and temperature (T) of a gas. By rearranging this equation, we can solve for different variables to determine specific properties of a gas.

Given Data

Mass of gas = 7.46 mg
Volume = 2899 mL
Pressure = 849 mm Hg = 1.117 atm
Temperature = 27.63°C = 300.78 K

Calculating the Number of Moles

First, we need to convert the temperature to Kelvin by adding 273.15 to the Celsius temperature. This gives us T = 27.63°C + 273.15 = 300.78 K.

Next, we convert the pressure from mm Hg to atm by dividing by 760. Therefore, 849 mm Hg / 760 mm Hg/atm = 1.117 atm.

Using the Ideal Gas Law formula to solve for the number of moles (n), we have n = (1.117 atm * 2899 mL / 1000 mL/L) / (0.0821 L atm mol⁻¹ K⁻¹ * 300.78 K).

Determining the Molecular Weight

Now that we have calculated the number of moles of the gas, we can proceed to find the molecular weight (MW) using the equation MW = mass (in grams) / moles. This translates to MW = 7.46 mg / 1000 mg/g / calculated moles.

By performing the necessary calculations, we will arrive at the molecular weight of the gas in grams per mole (g/mol).

By applying the principles of the Ideal Gas Law and understanding the relationships between different properties of gases, we can successfully determine the molecular weight of a gas based on experimental data. This problem-solving approach in chemistry not only strengthens our grasp of gas behavior but also enhances our analytical and critical thinking skills.

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