Compound Composition Calculation

How many moles of theoretical compound L2E3 would be in 25 g of the compound?

The molar mass of theoretical element L is 12.19. The molar mass of theoretical element E is 8.29. Round your answer to 2 decimal places.

1.08 moles of theoretical compound L2E3 in 25 g of the compound.

Answer:

The number of moles in 25 g of the compound L2E3 is 1.08 moles. But we need to find the number of moles of the theoretical compound L2E3 based on the given molar masses of elements L and E.

When calculating the number of moles of a compound based on a given mass, we use the formula: moles = mass / molar mass. In this case, the compound L2E3 consists of two atoms of L and three atoms of E. To find the molar mass of the compound L2E3, we calculate it based on the molar masses of element L and E.

The molar mass of L2E3 = 2 x molar mass of L + 3 x molar mass of E.

Substituting the values given:

Molar mass of L2E3 = 2 x 12.19 + 3 x 8.29

Molar mass of L2E3 = 24.38 + 24.87

Molar mass of L2E3 = 49.25 g/mol

Therefore, the number of moles of theoretical compound L2E3 in 25 g of the compound is approximately 0.51 moles.