How Many kJ of Heat Would be Released when 250g of Water Freezes?

How to find the amount of heat in kJ?

0.25 kg of water losing heat will generate about 83.39 kJ when frozen.

Answer:

C. 83.5 kJ

When 250g of water freezes, the amount of heat released can be calculated using the formula: Q = m × Lf.

Where Q is the released heat, m is the mass of the substance in kilograms, and Lf is its latent heat of fusion.

For water, the latent heat of fusion is 333.55 kJ/kg.

Therefore, for 0.25 kg of water:

Q = 0.25 kg * 333.55 kJ/kg

Q = 83.5 kJ

So, the amount of heat released when 250g of water freezes is 83.5 kJ.
← Reservoir drives and production decline rates in petroleum engineering How to calculate the pressure of ethane at a specific density and temperature →