How to Calculate Volume Using Boyle's Law

What is the volume of a 13.0 L sample of helium gas at 29.0 atm pressure?

A. 107.71 L

B. 108 L

C. 105.5 L

D. 110.2 L

Answer:

The correct answer is B. 108 L.

When dealing with Boyle's Law, which describes the relationship between the pressure and volume of a gas, you can use the equation P1V1 = P2V2. In this case, the initial pressure (P1) is 29.0 atm, the initial volume (V1) is 13.0 L, and the final pressure (P2) is 3.50 atm. We need to find the final volume (V2).

By substituting the values into the equation, we get (29.0 atm) * (13.0 L) = (3.50 atm) * (V2). Solving for V2 gives us V2 = (29.0 atm * 13.0 L) / (3.50 atm) = 108 L. Therefore, the volume of helium gas at 3.50 atm pressure would be 108 L.

This calculation aligns with Boyle's Law, which states that at a constant temperature, the product of pressure and volume is constant. As pressure decreases, volume increases proportionally to maintain the product constant.