# Preparation of Potassium Carbonate Solution

## How can we prepare a solution of potassium carbonate?

What volume of 0.340 M solution can be prepared from 15.6 g of potassium carbonate?

What is the formula to calculate the volume of the solution?

## Answer:

There are specific steps to prepare a solution of potassium carbonate from a given mass. The volume of the 0.340 M solution that can be prepared from 15.6 g of potassium carbonate is approximately 0.3318 liters.

**Introduction:** Potassium carbonate is a commonly used chemical compound with various applications in industries and laboratories. One of the common tasks in chemistry involves preparing a solution with a specific concentration from a given mass of a solute.

**Steps to prepare the solution:**

- Weigh 15.6 grams of potassium carbonate accurately using a digital balance.
- Calculate the number of moles of potassium carbonate using its molar mass.
- Determine the concentration of the desired solution (0.340 M in this case).
- Use the formula volume = moles / concentration to calculate the volume of the solution.
- Prepare the solution by dissolving the calculated amount of potassium carbonate in the required volume of solvent (usually water).

**Formula to calculate the volume of the solution:**
**volume (in liters) = mass (in grams) / molar mass (in grams per mole) / concentration (in moles per liter)**

**Explanation:** To prepare the 0.340 M solution of potassium carbonate:

- Calculate moles of potassium carbonate: 15.6 grams / 138.21 g/mol = 0.1127 mol
- Calculate volume of solution: 0.1127 mol / 0.340 mol/L = 0.3318 liters

**Conclusion:** By following the steps and using the formula mentioned above, we can successfully prepare a potassium carbonate solution with the desired concentration from a given mass. Understanding these concepts in chemistry allows us to perform various experiments and reactions effectively.