The Volume of Ice Calculation
The density of ice at 0°C is 0.917 g/mL. What is the volume of 58.2 g of ice?
a) 63.48 mL
b) 63.48 cm³
c) 63.48 L
d) 6.35 mL
Final answer: The volume of 58.2 g of ice, using the given density of ice at 0°C, is approximately 63.48 mL (or 63.48 cm³). This is obtained by using the formula for density (v = m/d). Explanation: To calculate the volume of ice, we use the formula for density which is mass divided by volume (d = m/v). We would rearrange the formula to solve for volume, so it becomes v = m/d. In this case, the mass (m) of ice is given as 58.2 g and the density (d) is given as 0.917 g/mL, we want to find the volume (v). So, we will do the division: v = 58.2 g / 0.917 g/mL = 63.47 mL, and we round it up to two decimal places. Therefore, the volume of 58.2 g of ice is approximately 63.48 mL. Notice that the unit used for volume here is mL (milliliters), which is a common unit of measurement in chemistry for volume. Also, please remember that 1 mL is equal to 1 cm³, therefore, the answer could also be expressed as 63.48 cm³. The density of ice at 0°C is 0.917 g/mL. What is the volume of 58.2 g of ice? The volume of 58.2 g of ice, using the given density of ice at 0°C, is approximately 63.48 mL (or 63.48 cm³). This is obtained by using the formula for density (v = m/d).