# A Battery Connected to a Light Bulb in a Circuit

## Understanding the Resistance of a Light Bulb in a Circuit

A battery is connected to a light bulb in a circuit. There is a current of **2 A** in the light bulb. The voltage of the battery is **1.5 V**.

## Calculating the Resistance

To find the resistance of the light bulb, we can use Ohm's Law. Ohm's Law states that *V = I * R*, where *V* is the voltage, *I* is the current, and *R* is the resistance.

Given that the current *I* is **2 A** and the voltage *V* is **1.5 V**, we can calculate the resistance as follows:

**Resistance (R) = Voltage (V) / Current (I)**

**Resistance (R) = 1.5 V / 2 A = 0.75 ohms**

## Answer:

The resistance of the light bulb in the circuit is **0.75 ohms**.

## Explanation:

The current in a circuit is directly proportional to the electric potential difference impressed across its ends and inversely proportional to the total resistance offered by the external circuit. The greater the battery voltage, the greater the current.

What is the resistance of the light bulb in the circuit? The resistance of the light bulb in the circuit is 0.75 ohms.