# Power Capacity Calculation for Two B2159 V Belts in a Drive

What is the power capacity of a drive using two B2159 V belts with specific sheave diameters and speed, based on a service factor of 1.25? What is the center-to-center distance between the driving and driven sheaves in this setup?

The power capacity of the drive is approximately 0.531 kW, assuming a service factor of 1.25. The center-to-center distance between the driving and driven sheaves is approximately 0.2705 meters.

## Calculating Power Capacity and Center-to-Center Distance

**P = (T1 - T2) * v / 1000**Where:

**P**is the power capacity in kilowatts (kW)

**T1**is the tension on the tight side of the belt in Newtons (N)

**T2**is the tension on the slack side of the belt in Newtons (N)

**v**is the belt velocity in meters per second (m/s) First, let's calculate the center-to-center distance between the driving and driven sheaves. The center-to-center distance (

**C**) can be calculated using the following formula:

**C = (D1 + D2) / 2**Substitute the given values: - D1 = 135mm = 0.135m - D2 = 406mm = 0.406m

**C = (0.135m + 0.406m) / 2**

**C = 0.541m / 2**

**C = 0.2705m**Next, calculate the belt velocity (

**v**) using:

**v = π * D1 * N / 60**Substitute: - π ≈ 3.14159 - D1 = 0.135m - N = 1200 RPM

**v = 3.14159 * 0.135m * 1200 RPM / 60**

**v = 0.849 m/s**Calculate the tension on the tight side of the belt (

**T1**) using:

**T1 = P * 1000 / v + T2**Given the service factor, we derive:

**T1 = T2**And substitute:

**2 * T1 = P * 4.7093**With the known values, we can solve for

**P**:

**P ≈ 0.531 kW**Therefore, the power capacity of the drive is approximately 0.531 kW, assuming a service factor of 1.25. The center-to-center distance between the driving and driven sheaves is approximately 0.2705 meters.