Calculating the Electric Field Between Plates of a Capacitor

What is the magnitude of the electric field between the plates of a capacitor with a 9V battery and plate separation of 2mm?

A. 4500V/m
B. 9000 V/m
C. 18 V/m
D. 18000V/m
E. 0 V/m

Answer:

The magnitude of the electric field between the plates of a parallel plate capacitor is 4500V/m.

The magnitude of the electric field between the plates of a parallel plate capacitor is directly proportional to the charge on the capacitor. In this case, a 9V battery is connected, so the potential difference across the plates is 9V. The plate separation is given as 2mm. The formula for the magnitude of the electric field is given by E = V/d, where V is the potential difference and d is the plate separation. Plugging in the values, we get E = 9V/0.002m = 4500V/m.

Therefore, the magnitude of the electric field between the plates when the capacitor is fully charged is 4500 V/m, which is option A.