Calculating Voltage Across a Resistor in a Series Circuit

What is the voltage across the 2300-Ω resistor?

Express your answer to two significant figures and include the appropriate units.

The voltage across the 2300-Ω resistor is approximately 9.68 V.

When a 550-Ω resistor and a 2300-Ω resistor are connected in series with a 12-V battery, the voltage across the 2300-Ω resistor can be calculated using Ohm's law. Ohm's law states that the voltage (V) across a resistor is equal to the current (I) flowing through it multiplied by the resistance (R) of the resistor.

Calculating Current in the Circuit:

To find the voltage across the 2300-Ω resistor, we first need to calculate the current flowing through the circuit. Since the two resistors are connected in series, the current flowing through both resistors is the same.

The total resistance (RT) in a series circuit is equal to the sum of the individual resistances:

RT = 550 Ω + 2300 Ω = 2850 Ω

Using Ohm's law, we can calculate the current (I) flowing through the circuit:

I = V / RT

I = 12 V / 2850 Ω

I ≈ 0.00421 A

Calculating Voltage Across the 2300-Ω Resistor:

Now that we know the current flowing through the circuit, we can calculate the voltage across the 2300-Ω resistor:

V = I * R

V = 0.00421 A * 2300 Ω

V ≈ 9.68 V

Therefore, the voltage across the 2300-Ω resistor is approximately 9.68 V.

← The power of displacement in solving distance problems Average speed determination using data visualizations →