Electric Potential Calculation in Point M and Point N
What is the distance of the point M and the point N from the charge Q?
The charge Q is located 40 cm away from the point M and 50 cm away from the point N. Given that the charge Q=1.2×10(-8)C in vacuum and the constant K=9×10^9 Nm^2/C.
What are the potentials at the point M and the point N?
The charge Q is located 40 cm away from the point M and 50 cm away from the point N. The distance between the charge Q and the points affects the electric potential at each point. To calculate the electric potential at each point, we can use the formula:
V = k * Q / r
Where:
V = Electric potential
k = Coulomb's constant (9×10^9 Nm^2/C)
Q = Charge (1.2×10(-8)C)
r = Distance from the charge
For the point M (40 cm away from Q), we can calculate the electric potential as follows:
VM = (9×10^9) * (1.2×10(-8)) / 0.4 = 270 V
For the point N (50 cm away from Q), we can calculate the electric potential as follows:
VN = (9×10^9) * (1.2×10(-8)) / 0.5 = 216 V
Therefore, the electric potential at point M is 270 volts and at point N is 216 volts.