How to Calculate Distance Traveled by a Car in 4 Seconds
What is the formula to calculate the distance traveled by a car when brought to rest uniformly in 4 seconds from an initial speed of 16 meters per second?
To calculate the distance traveled by a car when brought to rest uniformly in 4 seconds from an initial speed of 16 meters per second, we can use the formula for displacement: d = ut + (1/2)at² Where: - d is the displacement or distance traveled - u is the initial velocity - a is the acceleration - t is the time traveled First, let's find the acceleration using the formula (v - u) / t, where v is the final velocity, u is the initial velocity, and t is the time taken to reach the final velocity from the initial velocity. Given: - initial velocity, u = 16 m/s - final velocity, v = 0 m/s - time, t = 4 seconds Calculating acceleration: a = (v - u) / t a = (0 - 16) / 4 a = -16 / 4 a = -4 m/s² Plugging in the values of initial velocity (u = 16) and acceleration (a = -4) into the displacement formula: d = ut + (1/2)at² d = 16t - 2t d = 16 x 4 - 2 x 4 x 4 d = 64 - 32 d = 32 meters Therefore, the car travels a distance of 32 meters during the 4-second interval while being brought to rest uniformly from an initial speed of 16 meters per second.