Speed of a Stone Before Touching the Ground

What is the speed of a stone before touching the ground?

Choose the correct answer:

(a) 5.6 m/s

(b) 1.6 m/s

(c) 9.6 m/s

(d) 3 m/s

(e) none of these

Answer:

The speed of the stone before touching the ground is approximately 5.6 m/s.

To find the speed of the stone before touching the ground, we can use the equation v² = u² + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.

In this case, the stone is dropped, so the initial velocity is 0 m/s, the acceleration is the acceleration due to gravity (approximately 9.8 m/s²), and the distance traveled is the height of the building (1.6 meters).

Plugging in the values, we get:

v² = 0² + 2(9.8)(1.6)

v² = 31.36

v = √31.36

v ≈ 5.6 m/s

Therefore, the speed of the stone before touching the ground is approximately 5.6 m/s.