What Happens When One Lamp in a Three-Lamp Parallel Circuit Burns Out?

Explanation:

In a three-lamp parallel circuit, if one lamp burns out, the current in the other two lamps will remain the same. This is because in a parallel circuit, each lamp has its own branch, and the voltage across each branch is the same as the total voltage of the circuit.

Current Distribution: When one lamp burns out, the current that was flowing through it will be interrupted. However, the current will still flow through the other two lamps unaffected because each lamp has its own path for current to flow through.

Constant Potential Difference: The potential difference across the other two lamps will also remain constant. This is because the total potential difference in a parallel circuit is the same across all branches, regardless of the number of lamps.

Ohm's Law: According to Ohm's Law, V = IR, where V is the potential difference, I is the current, and R is the resistance. Since the resistance and potential difference across the other lamps do not change, their currents will also remain the same.