# Gas Pressure Calculation Using Ideal Gas Law

## How can we calculate the pressure exerted by an ideal gas in a given container?

Which of the following expressions is the correct way to calculate the pressure exerted by 1.85 mol of an ideal gas in a 3.00 L container at 35.0ºC?

a. (1.85)(.0821)(308)/3 atm

b. (1.85)(8.314)(308)/3 atm

c. 3/(.0821)(1.85)(308) atm

d. (1.85)(8.314)(308)/3 atm

e. (3)(1.85)/(.0821)(35) atm

## Answer:

The correct expression to calculate the pressure exerted by 1.85 mol of an ideal gas in a 3.00 L container at 35.0ºC is option b. (1.85)(8.314)(308) / 3 atm.

When calculating the pressure exerted by an ideal gas in a given container, we can use the ideal gas law equation PV = nRT. In this case, to find the pressure exerted by 1.85 mol of an ideal gas in a 3.00 L container at 35.0ºC, we need to plug in the given values into the ideal gas law equation.

Given values:

Number of moles (n) = 1.85 mol

Volume (V) = 3.00 L

Temperature (T) = 35.0ºC = 308 K (in Kelvin)

Substitute these values into the ideal gas law equation:

Pressure (P) × Volume (V) = Number of moles (n) × Ideal gas constant (R) × Temperature (T)

Simplify the equation:

Pressure (P) = (1.85)(8.314)(308) / 3 atm

Therefore, the correct expression to calculate the pressure exerted by 1.85 mol of an ideal gas in a 3.00 L container at 35.0ºC is option b. (1.85)(8.314)(308) / 3 atm.